If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-11x-37=0
a = 2; b = -11; c = -37;
Δ = b2-4ac
Δ = -112-4·2·(-37)
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{417}}{2*2}=\frac{11-\sqrt{417}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{417}}{2*2}=\frac{11+\sqrt{417}}{4} $
| 40x+12x=598 | | x-10x+83=-25 | | 15x=24x+6 | | −2x−4=20 | | 6=3+u/7.68 | | 2(6x+8)=52 | | 7m=5m=6 | | x+2=8x+3 | | 1/3x-1/2x=11/4 | | 9x+7=5x+4 | | 1x+7=5x+4 | | 5200/140=x/100 | | 615+x=900 | | s=(7-2)180=900 | | 10=10-5x+19 | | 11x-5=x+5 | | X.9.9=0.2x | | -4-6=2x+8 | | -1/4(8x-2/5)=1/8(4-2/3×) | | s=(9-2)180=900 | | 0.95x=0.80x+15 | | -6p+7=(6p-9)(40-16p) | | 2x-133=-19 | | 25x^2-256=0 | | 2x+4x=-25 | | x=41+5/8 | | 8x+2(20)+2(15)=102 | | -36a^2+48a-15=0 | | 14h+h-10h-4h=10 | | -7b-12b-(-7b)=12 | | 11x^2+11=12x | | -11k-(-7k)=-12 |